Optimal. Leaf size=206 \[ -\frac{3 e^6 (16 d-5 e x) \sqrt{d^2-e^2 x^2}}{16 x}+\frac{e^4 (16 d+5 e x) \left (d^2-e^2 x^2\right )^{3/2}}{16 x^3}-\frac{e^2 (24 d+5 e x) \left (d^2-e^2 x^2\right )^{5/2}}{40 x^5}-\frac{e \left (d^2-e^2 x^2\right )^{7/2}}{2 x^6}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{7 x^7}-3 d e^7 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )-\frac{15}{16} d e^7 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right ) \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.310915, antiderivative size = 206, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 9, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {1807, 811, 813, 844, 217, 203, 266, 63, 208} \[ -\frac{3 e^6 (16 d-5 e x) \sqrt{d^2-e^2 x^2}}{16 x}+\frac{e^4 (16 d+5 e x) \left (d^2-e^2 x^2\right )^{3/2}}{16 x^3}-\frac{e^2 (24 d+5 e x) \left (d^2-e^2 x^2\right )^{5/2}}{40 x^5}-\frac{e \left (d^2-e^2 x^2\right )^{7/2}}{2 x^6}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{7 x^7}-3 d e^7 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )-\frac{15}{16} d e^7 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right ) \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 1807
Rule 811
Rule 813
Rule 844
Rule 217
Rule 203
Rule 266
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{(d+e x)^3 \left (d^2-e^2 x^2\right )^{5/2}}{x^8} \, dx &=-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{7 x^7}-\frac{\int \frac{\left (d^2-e^2 x^2\right )^{5/2} \left (-21 d^4 e-21 d^3 e^2 x-7 d^2 e^3 x^2\right )}{x^7} \, dx}{7 d^2}\\ &=-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{7 x^7}-\frac{e \left (d^2-e^2 x^2\right )^{7/2}}{2 x^6}+\frac{\int \frac{\left (126 d^5 e^2+21 d^4 e^3 x\right ) \left (d^2-e^2 x^2\right )^{5/2}}{x^6} \, dx}{42 d^4}\\ &=-\frac{e^2 (24 d+5 e x) \left (d^2-e^2 x^2\right )^{5/2}}{40 x^5}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{7 x^7}-\frac{e \left (d^2-e^2 x^2\right )^{7/2}}{2 x^6}-\frac{\int \frac{\left (1008 d^7 e^4+210 d^6 e^5 x\right ) \left (d^2-e^2 x^2\right )^{3/2}}{x^4} \, dx}{336 d^6}\\ &=\frac{e^4 (16 d+5 e x) \left (d^2-e^2 x^2\right )^{3/2}}{16 x^3}-\frac{e^2 (24 d+5 e x) \left (d^2-e^2 x^2\right )^{5/2}}{40 x^5}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{7 x^7}-\frac{e \left (d^2-e^2 x^2\right )^{7/2}}{2 x^6}+\frac{\int \frac{\left (4032 d^9 e^6+1260 d^8 e^7 x\right ) \sqrt{d^2-e^2 x^2}}{x^2} \, dx}{1344 d^8}\\ &=-\frac{3 e^6 (16 d-5 e x) \sqrt{d^2-e^2 x^2}}{16 x}+\frac{e^4 (16 d+5 e x) \left (d^2-e^2 x^2\right )^{3/2}}{16 x^3}-\frac{e^2 (24 d+5 e x) \left (d^2-e^2 x^2\right )^{5/2}}{40 x^5}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{7 x^7}-\frac{e \left (d^2-e^2 x^2\right )^{7/2}}{2 x^6}-\frac{\int \frac{-2520 d^{10} e^7+8064 d^9 e^8 x}{x \sqrt{d^2-e^2 x^2}} \, dx}{2688 d^8}\\ &=-\frac{3 e^6 (16 d-5 e x) \sqrt{d^2-e^2 x^2}}{16 x}+\frac{e^4 (16 d+5 e x) \left (d^2-e^2 x^2\right )^{3/2}}{16 x^3}-\frac{e^2 (24 d+5 e x) \left (d^2-e^2 x^2\right )^{5/2}}{40 x^5}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{7 x^7}-\frac{e \left (d^2-e^2 x^2\right )^{7/2}}{2 x^6}+\frac{1}{16} \left (15 d^2 e^7\right ) \int \frac{1}{x \sqrt{d^2-e^2 x^2}} \, dx-\left (3 d e^8\right ) \int \frac{1}{\sqrt{d^2-e^2 x^2}} \, dx\\ &=-\frac{3 e^6 (16 d-5 e x) \sqrt{d^2-e^2 x^2}}{16 x}+\frac{e^4 (16 d+5 e x) \left (d^2-e^2 x^2\right )^{3/2}}{16 x^3}-\frac{e^2 (24 d+5 e x) \left (d^2-e^2 x^2\right )^{5/2}}{40 x^5}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{7 x^7}-\frac{e \left (d^2-e^2 x^2\right )^{7/2}}{2 x^6}+\frac{1}{32} \left (15 d^2 e^7\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{d^2-e^2 x}} \, dx,x,x^2\right )-\left (3 d e^8\right ) \operatorname{Subst}\left (\int \frac{1}{1+e^2 x^2} \, dx,x,\frac{x}{\sqrt{d^2-e^2 x^2}}\right )\\ &=-\frac{3 e^6 (16 d-5 e x) \sqrt{d^2-e^2 x^2}}{16 x}+\frac{e^4 (16 d+5 e x) \left (d^2-e^2 x^2\right )^{3/2}}{16 x^3}-\frac{e^2 (24 d+5 e x) \left (d^2-e^2 x^2\right )^{5/2}}{40 x^5}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{7 x^7}-\frac{e \left (d^2-e^2 x^2\right )^{7/2}}{2 x^6}-3 d e^7 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )-\frac{1}{16} \left (15 d^2 e^5\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{d^2}{e^2}-\frac{x^2}{e^2}} \, dx,x,\sqrt{d^2-e^2 x^2}\right )\\ &=-\frac{3 e^6 (16 d-5 e x) \sqrt{d^2-e^2 x^2}}{16 x}+\frac{e^4 (16 d+5 e x) \left (d^2-e^2 x^2\right )^{3/2}}{16 x^3}-\frac{e^2 (24 d+5 e x) \left (d^2-e^2 x^2\right )^{5/2}}{40 x^5}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{7 x^7}-\frac{e \left (d^2-e^2 x^2\right )^{7/2}}{2 x^6}-3 d e^7 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )-\frac{15}{16} d e^7 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right )\\ \end{align*}
Mathematica [C] time = 0.168598, size = 247, normalized size = 1.2 \[ -\frac{e^7 \left (d^2-e^2 x^2\right )^{7/2} \, _2F_1\left (3,\frac{7}{2};\frac{9}{2};1-\frac{e^2 x^2}{d^2}\right )}{7 d^6}-\frac{3 d^5 e^2 \sqrt{d^2-e^2 x^2} \, _2F_1\left (-\frac{5}{2},-\frac{5}{2};-\frac{3}{2};\frac{e^2 x^2}{d^2}\right )}{5 x^5 \sqrt{1-\frac{e^2 x^2}{d^2}}}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{7 x^7}+\frac{34 d^6 e^3 x^2-59 d^4 e^5 x^4+33 d^2 e^7 x^6+15 d^2 e^7 x^6 \sqrt{1-\frac{e^2 x^2}{d^2}} \tanh ^{-1}\left (\sqrt{1-\frac{e^2 x^2}{d^2}}\right )-8 d^8 e}{16 x^6 \sqrt{d^2-e^2 x^2}} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [B] time = 0.131, size = 377, normalized size = 1.8 \begin{align*} -{\frac{3\,{e}^{2}}{5\,d{x}^{5}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{7}{2}}}}+{\frac{2\,{e}^{4}}{5\,{d}^{3}{x}^{3}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{7}{2}}}}-{\frac{8\,{e}^{6}}{5\,{d}^{5}x} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{7}{2}}}}-{\frac{8\,{e}^{8}x}{5\,{d}^{5}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{5}{2}}}}-2\,{\frac{{e}^{8}x \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{3/2}}{{d}^{3}}}-3\,{\frac{{e}^{8}x\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}{d}}-3\,{\frac{d{e}^{8}}{\sqrt{{e}^{2}}}\arctan \left ({\frac{\sqrt{{e}^{2}}x}{\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}} \right ) }-{\frac{{e}^{3}}{8\,{d}^{2}{x}^{4}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{7}{2}}}}+{\frac{3\,{e}^{5}}{16\,{d}^{4}{x}^{2}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{7}{2}}}}+{\frac{3\,{e}^{7}}{16\,{d}^{4}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{5}{2}}}}+{\frac{5\,{e}^{7}}{16\,{d}^{2}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{3}{2}}}}+{\frac{15\,{e}^{7}}{16}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}-{\frac{15\,{e}^{7}{d}^{2}}{16}\ln \left ({\frac{1}{x} \left ( 2\,{d}^{2}+2\,\sqrt{{d}^{2}}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}} \right ) } \right ){\frac{1}{\sqrt{{d}^{2}}}}}-{\frac{e}{2\,{x}^{6}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{7}{2}}}}-{\frac{d}{7\,{x}^{7}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{7}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [A] time = 1.83584, size = 385, normalized size = 1.87 \begin{align*} \frac{3360 \, d e^{7} x^{7} \arctan \left (-\frac{d - \sqrt{-e^{2} x^{2} + d^{2}}}{e x}\right ) + 525 \, d e^{7} x^{7} \log \left (-\frac{d - \sqrt{-e^{2} x^{2} + d^{2}}}{x}\right ) + 560 \, d e^{7} x^{7} +{\left (560 \, e^{7} x^{7} - 2496 \, d e^{6} x^{6} - 525 \, d^{2} e^{5} x^{5} + 992 \, d^{3} e^{4} x^{4} + 770 \, d^{4} e^{3} x^{3} - 96 \, d^{5} e^{2} x^{2} - 280 \, d^{6} e x - 80 \, d^{7}\right )} \sqrt{-e^{2} x^{2} + d^{2}}}{560 \, x^{7}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [C] time = 24.0499, size = 1537, normalized size = 7.46 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [B] time = 1.22846, size = 689, normalized size = 3.34 \begin{align*} -3 \, d \arcsin \left (\frac{x e}{d}\right ) e^{7} \mathrm{sgn}\left (d\right ) - \frac{15}{16} \, d e^{7} \log \left (\frac{{\left | -2 \, d e - 2 \, \sqrt{-x^{2} e^{2} + d^{2}} e \right |} e^{\left (-2\right )}}{2 \,{\left | x \right |}}\right ) + \frac{{\left (5 \, d e^{16} + \frac{35 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )} d e^{14}}{x} + \frac{49 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{2} d e^{12}}{x^{2}} - \frac{245 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{3} d e^{10}}{x^{3}} - \frac{875 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{4} d e^{8}}{x^{4}} + \frac{455 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{5} d e^{6}}{x^{5}} + \frac{9065 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{6} d e^{4}}{x^{6}}\right )} x^{7} e^{5}}{4480 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{7}} - \frac{1}{4480} \,{\left (\frac{9065 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )} d e^{68}}{x} + \frac{455 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{2} d e^{66}}{x^{2}} - \frac{875 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{3} d e^{64}}{x^{3}} - \frac{245 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{4} d e^{62}}{x^{4}} + \frac{49 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{5} d e^{60}}{x^{5}} + \frac{35 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{6} d e^{58}}{x^{6}} + \frac{5 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{7} d e^{56}}{x^{7}}\right )} e^{\left (-63\right )} + \sqrt{-x^{2} e^{2} + d^{2}} e^{7} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]